Power Adapter Same Voltage Different Amp

Power Adapter Same Voltage Different Amp. It is doubled in voltage. Double the voltage in the same resistance also means double the current.

Power Adapter 12V 2 Amp J Tech Photonics, Inc.
Power Adapter 12V 2 Amp J Tech Photonics, Inc. from jtechphotonics.com

P = v * i. The voltage firure has to multiply by the amperage figure has to stack up to the requirement on the va figure printed on your battery or old charging unit. This doesnt mean your device will consume 3.42 a when its powered with this adapter;

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I have an old router with a 12v 1.5a rating, and its power supply died so im using a 12v 1.2a power supply. Power = voltage x current so the power is 2 x 2 = 4 times higher = 128mw in 32ω. I can use a laptop charger with the same voltage but higher rated amperage than my original, correct?

Amperage Rating On The Power Supply Is The Maximum Current It Can Provide At The Given Voltage.


The power formula p (watts) = i (ampere) x v (volts) shows you that if for example the needed power is 5 watts and the adapter delivers 12 volts, the adapter must be able to supply a current of at least 0,41 amps (or 410 ma). Overpowered is better than underpowered. (ie, 16v output instead of 12v with little or no load, dropping to 12v or so under a moderate load.) for power bricks, match voltage and type and a 2a supply will be fine for a phone that wants a minimum of 1.5a.

Since The Monitor Only Needs 1.5 Amps It Should Work Fine.


A power cable and a power adapter are different things but no matter. It is important to use the correct volts when choosing the adapter as a device can only run on the rated voltage. So power supply with a (much) higher amperage rating is ok.

P = Power (Watts) V = Voltage (Volts) I = Current (Amps) Looking Back At Our Example Of Water Flowing Through A Hose, We Can Now See How Power Is Directly Related To Current And Voltage Using This Equation.


Double the voltage in the same resistance also means double the current. P = v * i. This area of electronics is a still a little mysterious.

I Would Imagine That The Device In Question Would Only Draw The Amperage It Requires, Like A Computers Power Supply.


If i dont have the exact amperage, should i use higher or lower? The only caveat is that a (cheap) 20a power supply will probably overshoot the voltage on a very light load. Its possible to have a slight difference in voltage and amperage ratings for your device to work properly.

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